Eryk Sun added the comment:
For Python 3 you can also make it a keyword-only argument by adding a bare '*'
to the parameter list:
funcs = [(lambda x, *, t=t: x * t) for t in range(5)]
Code that accidentally calls funcs[0](3, 'silent bug ') will raise a TypeError
because "t" can only be passed as a keyword argument.
An alternative is to use another lambda instead of using a default argument:
funcs = [(lambda y: (lambda x: x * y))(t) for t in range(5)]
This lets you continue to use a closure (now over the temporary scope of the
outer call) and keep the function signature free of extra arguments. However,
using a keyword-only argument is obviously less obfuscated.
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nosy: +eryksun
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Python tracker <rep...@bugs.python.org>
<http://bugs.python.org/issue26361>
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