Senthil Kumaran added the comment: I think that we use encourage everyone to use the higher level functions like urlparse() or urlsplit() and then get the .port from the named tuple result.
Two things to do. 1. Update that Note the documentation which states a false statement that those helper functions are not exposed in urllib.parse 2. Raise a DeprecationWarning and rename them to _splitport() ---------- nosy: +orsenthil versions: -Python 3.2, Python 3.3, Python 3.4 _______________________________________ Python tracker <rep...@bugs.python.org> <http://bugs.python.org/issue27485> _______________________________________ _______________________________________________ Python-bugs-list mailing list Unsubscribe: https://mail.python.org/mailman/options/python-bugs-list/archive%40mail-archive.com
