Tim Peters added the comment:
Well, some backslash escapes are processed in the "replacement" argument to
`.sub()`. If your replacement text contains a substring of the form
\g
not immediately followed by
<
that will raise the exception you're seeing. The parser is expecting to see a
"matched group" reference after "\g", like
\g<1>
\g<name_of_named_group>
So it depends on the value of your `new_output`.
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<http://bugs.python.org/issue27586>
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