New submission from Kay Hayen:
Hello,
there is a regression in the beta (alpha 4 was ok) for this kind of code:
print("Complex call with both invalid star list and star arguments:")
try:
a = 1
b = 2.0
functionWithDefaults(1,c = 3,*a,**b)
except TypeError as e:
print(repr(e))
try:
a = 1
b = 2.0
functionWithDefaults(1,*a,**b)
except TypeError as e:
print(repr(e))
try:
a = 1
b = 2.0
functionWithDefaults(c = 1, *a,**b)
except TypeError as e:
print(repr(e))
try:
a = 1
b = 2.0
functionWithDefaults(*a,**b)
except TypeError as e:
print(repr(e))
This prints with beta1 3.6
Complex call with both invalid star list and star arguments:
TypeError("'int' object is not iterable",)
TypeError("'int' object is not iterable",)
TypeError("'float' object is not iterable",)
TypeError('functionWithDefaults() argument after ** must be a mapping, not
float',)
The later message is what they all probably should be like. This is 3.5 output:
Complex call with both invalid star list and star arguments:
TypeError('functionWithDefaults() argument after ** must be a mapping, not
float',)
TypeError('functionWithDefaults() argument after ** must be a mapping, not
float',)
TypeError('functionWithDefaults() argument after ** must be a mapping, not
float',)
TypeError('functionWithDefaults() argument after ** must be a mapping, not
float',)
The function itself doesn't matter obviously, it's never called. Please restore
the old behavior, thanks.
Yours,
Kay
----------
messages: 277270
nosy: kayhayen
priority: normal
severity: normal
status: open
title: Regression for star argument parameter error messages
type: behavior
versions: Python 3.6
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Python tracker <[email protected]>
<http://bugs.python.org/issue28257>
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