Nick Coghlan added the comment: (I'll also note that my final comment there is rather different from my first draft, as I almost forgot myself that the namespace preparation logic lives in __build_class__ rather than type_new. Class definitions can actually bypass type entirely, even in Python 3:
>>> def the_one_class(*args): ... return 1 ... >>> class TheOne(metaclass=the_one_class): pass ... >>> TheOne 1 ---------- _______________________________________ Python tracker <rep...@bugs.python.org> <http://bugs.python.org/issue28437> _______________________________________ _______________________________________________ Python-bugs-list mailing list Unsubscribe: https://mail.python.org/mailman/options/python-bugs-list/archive%40mail-archive.com
