steven Michalske added the comment: Argh, I swear I proofread this...
print([a[x] for x in [slice(y+3, y-1, -1) for y in range(0, len(a), 4)]]) [[], [7, 7, 6, 5]] Catching my explicit case, I changed my code to: print([a[x] for x in [slice(y+3, y-1 if y > 1 else None, -1) for y in range(0, len(a), 4)]]) [[3, 2, 1, 0], [7, 6, 5, 4]] Also, I could have done this... print(list(reversed([a[x] for x in [slice(y, y-4, -1) for y in range(-1, -len(a), -4)]]))) [[3, 2, 1, 0], [7, 6, 5, 4]] But, Yikes All those inverses! Side Note I wish we had partitioning in ranges/slices. a[::4] == [0, 4] a[::4:2] == [[0, 1], [4, 5]] a[::4:-4] == [[3, 2, 1, 0], [7, 6, 5, 4]] ---------- _______________________________________ Python tracker <rep...@bugs.python.org> <http://bugs.python.org/issue28882> _______________________________________ _______________________________________________ Python-bugs-list mailing list Unsubscribe: https://mail.python.org/mailman/options/python-bugs-list/archive%40mail-archive.com
