New submission from Marius Gedminas: Run the following script with Python 3.6.0rc1:
class O: pass o = O() for n in range(20): print(n) o.x = 42 o.__dict__.pop('x', None) You can observe the memory usage of the Python process growing exponentially. E.g. in bash: ulimit -v 1000000 # don't push other processes into swap please python3.6 break.py 0 1 2 3 4 5 6 7 8 9 10 11 Traceback (most recent call last): File "break.py", line 7, in <module> o.x = 42 MemoryError ---------- components: Interpreter Core messages: 282623 nosy: mgedmin priority: normal severity: normal status: open title: Memory leak in dict.pop() versions: Python 3.6, Python 3.7 _______________________________________ Python tracker <rep...@bugs.python.org> <http://bugs.python.org/issue28894> _______________________________________ _______________________________________________ Python-bugs-list mailing list Unsubscribe: https://mail.python.org/mailman/options/python-bugs-list/archive%40mail-archive.com