[issue16011] "in" should be consistent with return value of __contains__

[R. David Murray]

R. David Murray added the comment:

>>> bool(())
False
>>> bool([])
False
>>> bool('')
False

What you want to say is that 'in' coerces the result returned by __contains__ 
to a boolean value.

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<http://bugs.python.org/issue16011>
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