Serhiy Storchaka added the comment:
This is not about how a symbolic link is represented. This is about how the
operation of creating a symbolic link is represented. The first filename is the
first argument of os.symlink(), the second filename is the second argument. Try
to run
os.symlink('a', 'a_link')
os.symlink('b', 'a_link')
You should get an error:
FileExistsError: [Errno 17] File exists: 'b' -> 'a_link'
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<http://bugs.python.org/issue29657>
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