Nick Coghlan added the comment:
Minimalist proposal:
def hex(self, *, bytes_per_group=None, delimiter=" "):
"""B.hex() -> string of hex digits
B.hex(bytes_per_group=N) -> hex digits in groups separated by
*delimeter*
Create a string of hexadecimal numbers from a bytes object::
>>> b'\xb9\x01\xef'.hex()
'b901ef'
>>> b'\xb9\x01\xef'.hex(bytes_per_group=1)
'b9 01 ef'
"""
Alternatively, the grouping could be by digit rather than by byte:
def hex(self, *, group_digits=None, delimiter=" "):
"""B.hex() -> string of hex digits
B.hex(group_digits=N) -> hex digits in groups separated by *delimeter*
Create a string of hexadecimal numbers from a bytes object::
>>> b'\xb9\x01\xef'.hex()
'b901ef'
>>> b'\xb9\x01\xef'.hex(group_digits=2)
'b9 01 ef'
"""
One potential advantage of the `group_digits` approach is that it could be
fairly readily adapted to the hex/oct/bin builtins (although if we did that, it
would make the lack of a "dec" builtin for decimal formatting a bit weird)
----------
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Python tracker <[email protected]>
<http://bugs.python.org/issue22385>
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