New submission from Kit Yan Choi:
Given a zipfile with the following content:
subdir/
file1.txt
subdir/file2.txt
>>> archive = ZipFile(file_path, "r")
>>> f = archive.open("subdir/", "r")
>>>f.read()
b''
It is quite odd that the subdirectory can be opened as if it was an empty file.
One would expect it to raise.
One use case is that the archive is created using shutil.make_archive, which
includes the subdirectory paths in the namelist. Upon looping
ZipFile.namelist(), you end up opening a subdirectory and getting the empty
content, which should have led to error and prompted the developers to filter
the namelist first.
----------
messages: 296564
nosy: Kit Yan Choi
priority: normal
severity: normal
status: open
title: ZipFile.open treats directory path as empty file
type: behavior
versions: Python 2.7, Python 3.3, Python 3.4, Python 3.5
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Python tracker <rep...@bugs.python.org>
<http://bugs.python.org/issue30724>
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