Steven D'Aprano added the comment:
Python 3.4, 3.5 and 3.6 are in feature-freeze, so this enhancement can only
apply to 3.7.
You say that pathlib.Path "can't be subclassed", but then immediately show an
example of subclassing it:
>>> class MyPath(pathlib.Path):
... pass
...
Which works fine. If you run:
issubclass(MyClass, pathlib.Path)
it returns True. Unfortunately, it looks like your subclass broke one of the
class invariants, but you don't find out until you try to instantiate it:
>>> p = MyPath('/home')
Traceback (most recent call last):
...
AttributeError: type object 'MyPath' has no attribute '_flavour'
_flavour is a private attribute, and is not documented, so I don't think
subclassing is supported. If that is the case:
- the documentation should say that subclassing is not supported;
- or the Path class should actively prohibit subclassing (will
probably require a metaclass);
- or both.
If subclassing is supported, then I think there ought to be a better way than
this:
py> class MyPath(pathlib.Path):
... _flavour = pathlib.Path('.')._flavour
...
py> MyPath('.')
MyPath('.')
----------
nosy: +pitrou, steven.daprano
versions: -Python 3.4, Python 3.5, Python 3.6
_______________________________________
Python tracker <[email protected]>
<http://bugs.python.org/issue30957>
_______________________________________
_______________________________________________
Python-bugs-list mailing list
Unsubscribe:
https://mail.python.org/mailman/options/python-bugs-list/archive%40mail-archive.com
