Robert Schuppenies <[EMAIL PROTECTED]> added the comment: As I understood the long object allocation it is implemented as "PyObject_MALLOC(sizeof(PyVarObject) + size*sizeof(digit))" to avoid this allocation of extra 2 bytes. So from my understanding, the number 0 allocates memory for the reference count, type, and ob_size, whereas any other number allocates this plus additional memory required by the number of digits.
Looking at bool objects in Py3k, arn't they fixed-sized memory-wise, always allocating the the padded size of _longobject? > In any case, I also think this doesn't matter much either way. Why do you think so? _______________________________________ Python tracker <[EMAIL PROTECTED]> <http://bugs.python.org/issue3690> _______________________________________ _______________________________________________ Python-bugs-list mailing list Unsubscribe: http://mail.python.org/mailman/options/python-bugs-list/archive%40mail-archive.com
