New submission from Med Nezar BELLAZRAK <bellazra...@gmail.com>:
Hello,
So i discovered a small unusual behavior (tracking it down was time-consuming)
when using itertools.groupby(), i have checked the documentation and it states
that:
"The returned group is itself an iterator that shares the underlying iterable
with groupby(). Because the source is shared, when the groupby() object is
advanced, the previous group is no longer visible. So, if that data is needed
later, it should be stored as a list"
I do agree with this statement, though i believe a call to igroup successively
in the same iteration should yield the same result while now it returns the
correct igroup in the first call while the following call returns an empty list.
Here's a small code snippet that illustrates this behavior:
Code:
import itertools
mylist = [(1,2), (1,3), (2,5)]
for key, igroup in itertools.groupby(mylist, lambda x: x[0]):
print(list(igroup)) # prints the expected igroup
print(list(igroup)) # prints an empty list
print(list(igroup)) # prints an empty list
Output:
[(1, 2), (1, 3)]
[]
[]
[(2, 5)]
[]
[]
Thanks in advance for anyone who works on this issue
----------
components: Extension Modules
messages: 318014
nosy: Med Nezar BELLAZRAK
priority: normal
severity: normal
status: open
title: itertools.groupby() returned igroup is only callable once
type: behavior
versions: Python 3.6
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Python tracker <rep...@bugs.python.org>
<https://bugs.python.org/issue33681>
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