New submission from Marcelo Alves <marcelo.franco.al...@gmail.com>:
Different instances should have different bound method ids, since they have
different memory addresses, isn’t it? Example:
I have a class and two instances:
class MyClass:
def something():
pass
a = MyClass()
b = MyClass()
If we print `a.something` and `b.something`, we can see that they have
different memory addresses:
# a.something
<bound method MyClass.something of <__main__.MyClass object at 0x103438588>>
# b.something
<bound method MyClass.something of <__main__.MyClass object at 0x10342add8>>
This clear indicates that they aren’t the same, and we can confirm that
comparing both using the `is` operator:
>>> a.something is b.something
False
But the identity of both indicates that they are the same, according with the
doc of `is` and `id`:
>>> id(a.something)
4350192008
>>> id(b.something)
4350192008
The documentation of `is` says:
The operators is and is not test for object identity: x is y is true if and
only if x and y are the same object. x is not y yields the inverse truth value.
[6]
ref: https://docs.python.org/2/reference/expressions.html#is
And the documentation of `id` says:
Return the “identity” of an object. This is an integer (or long integer) which
is guaranteed to be unique and constant for this object during its lifetime.
Two objects with non-overlapping lifetimes may have the same id() value.
CPython implementation detail: This is the address of the object in memory.
Thanks!
----------
components: Interpreter Core
messages: 318057
nosy: celicoo
priority: normal
severity: normal
status: open
title: Instances bound methods with different memory addresses but sharing same
id
type: behavior
versions: Python 3.6
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Python tracker <rep...@bugs.python.org>
<https://bugs.python.org/issue33685>
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