X. Yan <xg...@yorku.ca> added the comment:
Hi Serhiy, Thanks for your reply. However, the issue I reported was not about sharing the default value. I understand that the parameter L would keep its value [1] from function f's first run, and used it in the second run to get [1, 2]. My point is that the variable v1 only got involved in f's first run. It should keep the result [1] since then. The second calling v2=f(2) is irrelevant to v1, therefore, v1's content shouldn't be changed. v1 should be independent from f's later activities. Please let me know if this makes sense. ---------- status: closed -> open _______________________________________ Python tracker <rep...@bugs.python.org> <https://bugs.python.org/issue33835> _______________________________________ _______________________________________________ Python-bugs-list mailing list Unsubscribe: https://mail.python.org/mailman/options/python-bugs-list/archive%40mail-archive.com
