New submission from Erick Tryzelaar <[EMAIL PROTECTED]>: I ran into a case where I modified the __name__ attribute of a function and then didn't specify the right number of arguments, and I got a TypeError that used the original function name, as demonstrated here:
>>> def foo(): pass ... >>> foo.__name__ = 'bar' >>> foo(1) Traceback (most recent call last): File "<stdin>", line 1, in <module> TypeError: foo() takes no arguments (1 given) I would have expected it to say "TypeError: bar() ...". I'm guessing that the interpreter isn't using the __name__ attribute in this case. ---------- components: Library (Lib) messages: 75853 nosy: erickt severity: normal status: open title: function with modified __name__ uses original name when there's an arg error type: behavior versions: Python 3.0 _______________________________________ Python tracker <[EMAIL PROTECTED]> <http://bugs.python.org/issue4322> _______________________________________ _______________________________________________ Python-bugs-list mailing list Unsubscribe: http://mail.python.org/mailman/options/python-bugs-list/archive%40mail-archive.com
