Raymond Hettinger <raymond.hettin...@gmail.com> added the comment:
The open question in my mind is which is the least surprising definition of a//b. Should it be math.floor(a/b) or divmod(a,b)[0]? The advantage of the former is that floor(a/b) is arguably the definition of floor division. The advantage of the latter is that a//b, a%b, and divmod(a,b) are consistent with one another. FWIW, it looks like NumPy and PyPy made the same design choice as CPython: >>> a = numpy.array([4.0, 4.0, 4.0], dtype=numpy.float64) >>> b = numpy.array([0.4, 0.5, 0.6], dtype=numpy.float64) >>> a / b array([10. , 8. , 6.66666667]) >>> a // b array([9., 8., 6.]) $ pypy3 Python 3.5.3 (fdd60ed87e941677e8ea11acf9f1819466521bf2, Apr 26 2018, 01:25:35) [PyPy 6.0.0 with GCC 4.2.1 Compatible Apple LLVM 9.1.0 (clang-902.0.39.1)] on darwin Type "help", "copyright", "credits" or "license" for more information. >>>> 4.0 / 0.4 10.0 >>>> 4.0 // 0.4 9.0 ---------- _______________________________________ Python tracker <rep...@bugs.python.org> <https://bugs.python.org/issue36028> _______________________________________ _______________________________________________ Python-bugs-list mailing list Unsubscribe: https://mail.python.org/mailman/options/python-bugs-list/archive%40mail-archive.com
