Raymond Hettinger <raymond.hettin...@gmail.com> added the comment:
The code in the minimal example isn't creating nested frozensets. Instead, if
is converting one frozenset into another (because frozenset takes an iterable
as an argument). This is no different than list(list(list())) producing a
single list rather than a nested list.
Here's how to build nested frozensets:
>>> x = frozenset({})
>>> y = frozenset({x})
>>> z = frozenset({y})
>>> x
frozenset()
>>> y
frozenset({frozenset()})
>>> z
frozenset({frozenset({frozenset()})})
>>> x is y
False
>>> x == y
False
----------
resolution: -> not a bug
stage: -> resolved
status: open -> closed
_______________________________________
Python tracker <rep...@bugs.python.org>
<https://bugs.python.org/issue36507>
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