wim glenn <wim.gl...@gmail.com> added the comment:
Serhiy, `a, *L[::2] = "abc"` as an alternative is interesting, thanks. The other example `L[:], *rest = 'abcdef'` is less interesting because L[:] can be arbitrary size. When noticing this, I had tried to consume a generator into every other position in a list by using: L[::2], *extra = g Though there are obvious workarounds (e.g. using `itertools.islice`), it surprised me that CPython did not "do what I mean" out of the box. However, since creating the issue, it was brought to my attention that trying to handle this assignment may result in potential ambiguity, for example: L = [0, 1, 2] L[::2], *rest = "ab", "c", "d" There is no obvious choice for result here. So, perhaps this issue should just be closed. ---------- _______________________________________ Python tracker <rep...@bugs.python.org> <https://bugs.python.org/issue36761> _______________________________________ _______________________________________________ Python-bugs-list mailing list Unsubscribe: https://mail.python.org/mailman/options/python-bugs-list/archive%40mail-archive.com