New submission from Francesco Ricciardi <[EMAIL PROTECTED]>:
Each entry of a zip file, as read by the zipfile module, can be accessed
via a ZipInfo object. The filename attribute of ZipInfo is a string.
However, the read method of a ZipFile object expects a binary as
argument, or at least this is what I can deduct from the following behavior:
>>> import zipfile
>>> testzip = zipfile.ZipFile('test.zip')
>>> t1 = testzip.infolist()[0]
>>> t1.filename
'tést.xml'
>>> data = testzip.read(testzip.infolist()[0])
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
File "C:\Python30\lib\zipfile.py", line 843, in read
return self.open(name, "r", pwd).read()
File "C:\Python30\lib\zipfile.py", line 883, in open
% (zinfo.orig_filename, fname))
zipfile.BadZipfile: File name in directory 'tést.xml' and header
b't\x82st.xml' differ.
The test.zip file is attached as help in reproducing this error.
----------
components: Library (Lib)
files: test.zip
messages: 77555
nosy: francescor
severity: normal
status: open
title: zipfile returns string but expects binary
type: behavior
versions: Python 3.0
Added file: http://bugs.python.org/file12319/test.zip
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Python tracker <[EMAIL PROTECTED]>
<http://bugs.python.org/issue4621>
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