Terry J. Reedy <tjre...@udel.edu> added the comment:
https://docs.python.org/3/reference/lexical_analysis.html#string-and-bytes-literals says, for \ooo, "In a bytes literal, hexadecimal and octal escapes denote the byte with the given value. In a string literal, these escapes denote a Unicode character with the given value." I agree that sometimes truncating an invalid integer instead of always raising ValueError is strange. >>> ord(b'\407') 7 >>> bytes((0o407,)) ... ValueError: bytes must be in range(0, 256) I don't know is there was an intentional back-compatibility reason for this. Without an example of re raising, I don't understand the re complaint. ---------- nosy: +terry.reedy _______________________________________ Python tracker <rep...@bugs.python.org> <https://bugs.python.org/issue37367> _______________________________________ _______________________________________________ Python-bugs-list mailing list Unsubscribe: https://mail.python.org/mailman/options/python-bugs-list/archive%40mail-archive.com
