New submission from Andy Papageorgiou <andy.papageorg...@gmail.com>:
Wireshark reports two identical back to back packets sent for each sendto(),
timing between packets is between 2 and 10us.
Note this is on a point to point ethernet (just 1 cable, no switches, routers
or anything else in between) to an embedded platform (Zynq ARM) from an intel
i7 Window 10 laptop from 2018. The python code is running on the laptop.
python code:
with socket.socket(socket.AF_INET, socket.SOCK_DGRAM) as s:
s.bind(('', 5704))
while(more_to_send == TRUE)
<code to populate bytes_to_send>
s.sendto(bytes_to_send, (HOST, UDP_PORT))
data = s.recv(1024)
Wireshark log.
43204 80.146000 192.168.1.20 192.168.1.10 UDP 566 5704 →
5604 Len=524 (payload)
43205 80.146003 192.168.1.20 192.168.1.10 UDP 566 5704 →
5604 Len=524 (duplicate at payload time + 3us)
43206 80.149112 192.168.1.10 192.168.1.20 UDP 48 5604 →
5704 Len=6 (ack)
43207 80.149306 192.168.1.20 192.168.1.10 UDP 566 5704 →
5604 Len=524 (payload)
43208 80.149311 192.168.1.20 192.168.1.10 UDP 566 5704 →
5604 Len=524 (duplicate at payload time +5us)
I am suspicious this is an artefact of the point to point link.
----------
components: Library (Lib)
messages: 347614
nosy: Andy Papageorgiou
priority: normal
severity: normal
status: open
title: UDP sendto() sends duplicate packets
versions: Python 3.7
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Python tracker <rep...@bugs.python.org>
<https://bugs.python.org/issue37542>
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