Antoine Pietri <antoine.piet...@gmail.com> added the comment:
Actually I don't think it's possible with the current implementation to cancel the concurrent.Future after a timeout, so maybe we should remove that argument. So, this signature instead: async def create_thread(callable, *args, *, kwargs=None, loop=None) ---------- _______________________________________ Python tracker <rep...@bugs.python.org> <https://bugs.python.org/issue38306> _______________________________________ _______________________________________________ Python-bugs-list mailing list Unsubscribe: https://mail.python.org/mailman/options/python-bugs-list/archive%40mail-archive.com
