Steven D'Aprano <[email protected]> added the comment:
Why would they give the same result when the code is different?
#1 assign c, d, e and everything left over goes into b
*b, c, d, e, = [1, 2, 3, 4]
#2 assign c, d and everything left over goes into b
*b, c, d, = [1, 2, 3, 4]
#3 assign c and everything left over goes into b
*b, c, = [1, 2, 3, 4]
#4 assign nothing and everything left over goes into b
*b, = [1, 2, 3, 4]
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nosy: +steven.daprano
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<https://bugs.python.org/issue38516>
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