Ma Lin <malin...@163.com> added the comment:
An simpler reproduce code:
```
import re
NUM = 99
# items = [ '(001)', '(002)', '(003)', ..., '(NUM)']
items = [r'(%03d)' % i for i in range(1, 1+NUM)]
pattern = '|'.join(items)
# repl = '\1\2\3...\NUM'
temp = ('\\' + str(i) for i in range(1, 1+NUM))
repl = ''.join(temp)
text = re.sub(pattern, repl, '(001)')
print(text)
# if NUM == 99
# output: (001)
# if NUM == 100
# output: (001@)
# if NUM == 101
# output: (001@A)
```
----------
components: +Regular Expressions
nosy: +ezio.melotti, mrabarnett
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Python tracker <rep...@bugs.python.org>
<https://bugs.python.org/issue38582>
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