Ma Lin <[email protected]> added the comment:
An simpler reproduce code:
```
import re
NUM = 99
# items = [ '(001)', '(002)', '(003)', ..., '(NUM)']
items = [r'(%03d)' % i for i in range(1, 1+NUM)]
pattern = '|'.join(items)
# repl = '\1\2\3...\NUM'
temp = ('\\' + str(i) for i in range(1, 1+NUM))
repl = ''.join(temp)
text = re.sub(pattern, repl, '(001)')
print(text)
# if NUM == 99
# output: (001)
# if NUM == 100
# output: (001@)
# if NUM == 101
# output: (001@A)
```
----------
components: +Regular Expressions
nosy: +ezio.melotti, mrabarnett
_______________________________________
Python tracker <[email protected]>
<https://bugs.python.org/issue38582>
_______________________________________
_______________________________________________
Python-bugs-list mailing list
Unsubscribe:
https://mail.python.org/mailman/options/python-bugs-list/archive%40mail-archive.com
