Tim Peters <t...@python.org> added the comment:
Yes, what Steven said. All kinds of functions (including, but not limited to, generator-iterators) are compared by object identity, nothing at all about internal state. The contract of hash() is that if a == b, then we must have that hash(a) == hash(b) too. That's got nothing to do with internal state either, _only_ with how __eq__ is implemented. There is no sense in which any kind of function object is "mutable" that has any effect on its object identity, so also no sense in which it can affect __eq__ results, so no reason at all for __hash__ to care. It's all working as designed and as intended. ---------- _______________________________________ Python tracker <rep...@bugs.python.org> <https://bugs.python.org/issue38769> _______________________________________ _______________________________________________ Python-bugs-list mailing list Unsubscribe: https://mail.python.org/mailman/options/python-bugs-list/archive%40mail-archive.com
