Serhiy Storchaka <[email protected]> added the comment:
Your implementation takes several lines of code only because of complex
semantic of findall() which you want to preserve in findfirst(). Actually
findall() is an equivalent of one of three expressions, depending on the number
of capturing groups in the regular expression:
[m[0] for m in finditer(...)]
[m[1] for m in finditer(...)]
[m.groups() for m in finditer(...)]
so findfirst() is an equivalent of one of three expressions:
search(...)[0]
search(...)[1]
search(...).groups()
In real code the number of capturing groups in the regular expression you use
is known statically, so you should not dispatch one of above variants at run
time. You just use the appropriate one.
findall() is older interface. More modern, generator and object interface is
finditer(). findall() was not deprecated and was not converted to returning an
iterator because many old code uses it, and we do not want to break it.
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<https://bugs.python.org/issue39165>
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