New submission from Jaap Woldringh <jjhwoldri...@ziggo.nl>: Python used: Python 3.6.9 (default, Nov 7 2019, 10:44:02) [GCC 8.3.0] on linux Type "help", "copyright", "credits" or "license" for more information. In Ubuntu 18.04.3
But in any other version of Python3, and Python2, that I tried, the behaviour of a (square) matrix depends on how it is created; as I can demonstrate in a test program matrix_experiment.py that is attached to this report. 1. it behaves as expected when created by entering all it’s elements like so: A = [[ 1,2,3],[1,2,3],[1,2,3]] 2. If it is created by appending predefined rows, it behaves as if all rows are the same as the last row: row = [1,2,3] B=[] for i in range(3): B.appends(row) The result matrix is the same as A: [[1, 2, 3], [1, 2, 3], [1, 2, 3]] Both results are equal: print(A==B) gives True. But when using B the result is disastrous as the attached matrix_experiment.py program shows. I consider this a very serious bug, and first filed it at Ubuntu’s Launchpad, but I don't find it there. So now I file this again, at Python.org itself, using my new account. ---------- components: Tests files: matrix_experiment.py messages: 360182 nosy: jjhwoldringh priority: normal severity: normal status: open title: A matrix (list of lists) behaves differently, depending how it is created type: behavior versions: Python 3.6 Added file: https://bugs.python.org/file48849/matrix_experiment.py _______________________________________ Python tracker <rep...@bugs.python.org> <https://bugs.python.org/issue39368> _______________________________________ _______________________________________________ Python-bugs-list mailing list Unsubscribe: https://mail.python.org/mailman/options/python-bugs-list/archive%40mail-archive.com