STINNER Victor <vstin...@python.org> added the comment:
I reopen the issue. The following code works on Python 3.8, but fails with SyntaxError on Python 3.9.0a6 with the old and the new parser (see bpo-40431): clear = "NORMAL" print(dict(state=clear, bg="#d00" if clear else"#fca")) Well, the code looks like a typo error... but it worked previously. Not sure if we should keep the SyntaxError or not. Fixing the code is trivial: see PR 19777 attached to bpo-40431; replace >else"#fca"< with >else "#fca"<. Note: I first reported the issue to https://bugs.python.org/issue40334#msg367580 ---------- resolution: fixed -> status: closed -> open _______________________________________ Python tracker <rep...@bugs.python.org> <https://bugs.python.org/issue40246> _______________________________________ _______________________________________________ Python-bugs-list mailing list Unsubscribe: https://mail.python.org/mailman/options/python-bugs-list/archive%40mail-archive.com