Pablo Galindo Salgado <[email protected]> added the comment:
>But then why I still can access this variable? Shouldn't it then be
resulting in NameError as it's undefined variable at this point of time?
I don't think so, this is the same as if you do:
def f(exc):
del exc
return exc
>>> f(3)
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
File "lel.py", line 3, in f
return exc
UnboundLocalError: local variable 'exc' referenced before assignment
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Python tracker <[email protected]>
<https://bugs.python.org/issue40728>
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