Pablo Galindo Salgado <pablog...@gmail.com> added the comment:
>But then why I still can access this variable? Shouldn't it then be
resulting in NameError as it's undefined variable at this point of time?
I don't think so, this is the same as if you do:
def f(exc):
del exc
return exc
>>> f(3)
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
File "lel.py", line 3, in f
return exc
UnboundLocalError: local variable 'exc' referenced before assignment
----------
_______________________________________
Python tracker <rep...@bugs.python.org>
<https://bugs.python.org/issue40728>
_______________________________________
_______________________________________________
Python-bugs-list mailing list
Unsubscribe:
https://mail.python.org/mailman/options/python-bugs-list/archive%40mail-archive.com
