Tim Peters <t...@python.org> added the comment:
Cute: for any number of arguments, try computing h**2, then one at a time
subtract a**2 (an argument squared) in descending order of magnitude. Call
that (h**2 - a1**2 - a2**2 - ...) x.
Then
h -= x/(2*h)
That should reduce errors too, although not nearly so effectively, since it's a
cheap way of estimating (& correcting for) the discrepancy between sum(a**2)
and h**2.
Note that "descending order" is important: it's trying to cancel as many
leading bits as possible as early as possible, so that lower-order bits come
into play.
Then again ... why bother? ;-)
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Python tracker <rep...@bugs.python.org>
<https://bugs.python.org/issue41513>
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