New submission from 赵豪杰 <1292756...@qq.com>: ``` >>> import re >>> text = '121212 and 121212' >>> pattern = '(12)+' >>> print(re.findall(pattern, text)) ['12', '12'] >>> >>> >>> print(re.search(pattern, text)) <re.Match object; span=(0, 6), match='121212'> >>> >>> >>> print(re.sub(pattern, '', text)) and # The re.findall have different search result against re.search or re.sub # re.findall 和 re.search 、 re.sub 的匹配结果不相同 ```
With same pattern and string, the re.findall is supposed to have same match with re.search, but it didn't. This result is from python3.8.5 ---------- components: Regular Expressions messages: 381689 nosy: HaujetZhao, ezio.melotti, mrabarnett priority: normal severity: normal status: open title: re.findall have different match result against re.search or re.sub type: behavior versions: Python 3.8 _______________________________________ Python tracker <rep...@bugs.python.org> <https://bugs.python.org/issue42448> _______________________________________ _______________________________________________ Python-bugs-list mailing list Unsubscribe: https://mail.python.org/mailman/options/python-bugs-list/archive%40mail-archive.com
