Tim Peters <t...@python.org> added the comment:
There's no bug here. "&" is the bitwise Boolean logical-and operator on integers. For example, >>> 1 & 2 0 >>> 1 & 3 1 It binds more tightly than the "==" equality-testing operator. To get the result you want, you would need to add more parentheses to override the natural operator precedence: >>> (a == 10) & (not(a!=b)) & (b == 10) True But, more to the point, what you probably really want is the "and" logical operator, not the bitwise integer "&" operator: >>> a == 10 and (not(a!=b)) and b == 10 True ---------- nosy: +tim.peters resolution: -> not a bug stage: -> resolved status: open -> closed _______________________________________ Python tracker <rep...@bugs.python.org> <https://bugs.python.org/issue42456> _______________________________________ _______________________________________________ Python-bugs-list mailing list Unsubscribe: https://mail.python.org/mailman/options/python-bugs-list/archive%40mail-archive.com
