Robert <[email protected]> added the comment:
# `__main__` of the source code directory: `/tmp/rebound/rebound`.
# differentiate `__main__` of my target source code to read from the built-in
`__main__`? In other words, how do I read the module `__main__` of the
codebase: rebound?
=> when __main__.py is inside a package, use the full dotted module name - and
an appropriate search path below that directory:
pyclbr.readmodule_ex('rebound.__main__')
pyclbr.readmodule_ex('lib2to3.__main__')
When __main__.py is intended as a top level module / script, I think such a
name collision with an internal module name is a bad idea at all.
(For a special local purposes you could use a symlink or so?)
(I experience a bug with pyclbr (in py3.10 at least) when it traverses an
"import __main__" statement. It causes also "ValueError: __main__.__spec__ is
None" or "ValueError: {}.__spec__ is not set". But this seems to be an actual
bug w/o bug report so far: #43299 )
----------
nosy: +kxrob
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<https://bugs.python.org/issue43247>
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