Pablo Galindo Salgado <pablog...@gmail.com> added the comment:

I think is correct:

parameter_list ::= defparameter ("," defparameter)* "," "/" ["," 
[parameter_list_no_posonly]] | parameter_list_no_posonly

Says "a parameter_list" is either:

defparameter ("," defparameter)* "," "/" ["," [parameter_list_no_posonly]] 

or

parameter_list_no_posonly

If you don't use the "/" then is the second option.

Feel free to reopen if I am missing something.

----------
resolution:  -> not a bug
stage:  -> resolved
status: open -> closed

_______________________________________
Python tracker <rep...@bugs.python.org>
<https://bugs.python.org/issue44038>
_______________________________________
_______________________________________________
Python-bugs-list mailing list
Unsubscribe: 
https://mail.python.org/mailman/options/python-bugs-list/archive%40mail-archive.com

Reply via email to