Pablo Galindo Salgado <[email protected]> added the comment:
I think is correct:
parameter_list ::= defparameter ("," defparameter)* "," "/" [","
[parameter_list_no_posonly]] | parameter_list_no_posonly
Says "a parameter_list" is either:
defparameter ("," defparameter)* "," "/" ["," [parameter_list_no_posonly]]
or
parameter_list_no_posonly
If you don't use the "/" then is the second option.
Feel free to reopen if I am missing something.
----------
resolution: -> not a bug
stage: -> resolved
status: open -> closed
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<https://bugs.python.org/issue44038>
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