Pablo Galindo Salgado <pablog...@gmail.com> added the comment:
I think is correct: parameter_list ::= defparameter ("," defparameter)* "," "/" ["," [parameter_list_no_posonly]] | parameter_list_no_posonly Says "a parameter_list" is either: defparameter ("," defparameter)* "," "/" ["," [parameter_list_no_posonly]] or parameter_list_no_posonly If you don't use the "/" then is the second option. Feel free to reopen if I am missing something. ---------- resolution: -> not a bug stage: -> resolved status: open -> closed _______________________________________ Python tracker <rep...@bugs.python.org> <https://bugs.python.org/issue44038> _______________________________________ _______________________________________________ Python-bugs-list mailing list Unsubscribe: https://mail.python.org/mailman/options/python-bugs-list/archive%40mail-archive.com