New submission from Manuel Hermann <manuel-herm...@gmx.net>:
When sending unexpected data via a socket's sentdo method, a TypeError
is raised with the fallowing message: "sendto() takes exactly 3
arguments (2 given)". But two arguments are sufficient.
Examples for Python 2.x:
import socket
my_socket = socket.socket(socket.AF_INET, socket.SOCK_DGRAM)
# this will succeed
my_socket.sendto("Foobar", ("localhost", 514))
# these will fail with above error message
my_socket.sendto(u"Umlaut รค", ("localhost", 514))
my_socket.sendto(1, ("localhost", 514))
Examples for Python 3:
import socket
my_socket = socket.socket(socket.AF_INET, socket.SOCK_DGRAM)
# this will succeed
my_socket.sendto("No Umlaut".encode("ascii"), ("localhost", 514))
# these will fail with above error message
my_socket.sendto("No Umlaut", ("localhost", 514))
my_socket.sendto(1, ("localhost", 514))
----------
components: Library (Lib)
messages: 83187
nosy: helduel
severity: normal
status: open
title: Irritating error message by socket's sendto method
versions: Python 2.4, Python 2.5, Python 2.6, Python 3.0
_______________________________________
Python tracker <rep...@bugs.python.org>
<http://bugs.python.org/issue5421>
_______________________________________
_______________________________________________
Python-bugs-list mailing list
Unsubscribe:
http://mail.python.org/mailman/options/python-bugs-list/archive%40mail-archive.com
