Jason R. Coombs <jar...@jaraco.com> added the comment:

Even simpler:

```
zip_file = zipfile.ZipFile('zipfile.zip')
name = zip_file.namelist()[0]
zipfile.Path(zip_file)
zip_file.open(name)
```

----------

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Python tracker <rep...@bugs.python.org>
<https://bugs.python.org/issue44638>
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