Serhiy Storchaka <[email protected]> added the comment:
It works as expected:
>>> re.sub(r'\W', '', '½ a', 0, re.ASCII)
'a'
You just passed re.ASCII as the count argument, not as the flags argument.
>>> help(re.sub)
Help on function sub in module re:
sub(pattern, repl, string, count=0, flags=0)
Return the string obtained by replacing the leftmost
non-overlapping occurrences of the pattern in string by the
replacement repl. repl can be either a string or a callable;
if a string, backslash escapes in it are processed. If it is
a callable, it's passed the Match object and must return
a replacement string to be used.
----------
nosy: +serhiy.storchaka
resolution: -> not a bug
stage: -> resolved
status: open -> closed
_______________________________________
Python tracker <[email protected]>
<https://bugs.python.org/issue45458>
_______________________________________
_______________________________________________
Python-bugs-list mailing list
Unsubscribe:
https://mail.python.org/mailman/options/python-bugs-list/archive%40mail-archive.com
