New submission from Xinmeng Xia <[email protected]>:
Normally after executing a piece of code in a function, locals() should contain
the local variables and these variables can be reassigned next. In the
following code, "attr" should be found in locals(). Actually, it can not be
found in either locals() or globals() after executing code "attr = 1". This
program triggers a keyError. I think something wrong during handling locals().
================================
def foo():
exec("attr = 1")
a = locals()['attr']
attr = 2
foo()
================================
Reported Error:
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
File "<stdin>", line 3, in foo
KeyError: 'attr'
Expected output:
This test program should work well. The value of a is 1 and the value of attr
is 2 after execution. No error is reported.
Python version: python3.10, Ubuntu 16.04
----------
components: Interpreter Core
messages: 405660
nosy: xxm
priority: normal
severity: normal
status: open
title: Variable reassginment triggers incorrect behaviors of locals()
type: behavior
versions: Python 3.10
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Python tracker <[email protected]>
<https://bugs.python.org/issue45707>
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