Quentin Peter <[email protected]> added the comment:
The reason I am asking is that I am working on a debugger. The debugger stops
on a frame which is inside a function. Let's say the locals is:
locals() == {"a": 1}
I now want to define a closure with exec. I might want to do something like:
exec("def f(): return a", globals(), locals())
But this doesn't work because of the issue I describe.I would expect f() to
look for a in the locals().
Even more surprising is that if I use the second argument of exec, the code in
the above comment starts to fail.
----------
_______________________________________
Python tracker <[email protected]>
<https://bugs.python.org/issue46153>
_______________________________________
_______________________________________________
Python-bugs-list mailing list
Unsubscribe:
https://mail.python.org/mailman/options/python-bugs-list/archive%40mail-archive.com
