Mark Dickinson <dicki...@gmail.com> added the comment:
FWIW, when this need has turned up for me (which it has, a couple of times),
I've used this:
def risqrt(n):
return (isqrt(n<<2) + 1) >> 1
But I'll admit that that's a bit non-obvious.
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Python tracker <rep...@bugs.python.org>
<https://bugs.python.org/issue46187>
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