Mark Dickinson <[email protected]> added the comment:
FWIW, when this need has turned up for me (which it has, a couple of times),
I've used this:
def risqrt(n):
return (isqrt(n<<2) + 1) >> 1
But I'll admit that that's a bit non-obvious.
----------
_______________________________________
Python tracker <[email protected]>
<https://bugs.python.org/issue46187>
_______________________________________
_______________________________________________
Python-bugs-list mailing list
Unsubscribe:
https://mail.python.org/mailman/options/python-bugs-list/archive%40mail-archive.com
