Mike Auty <[email protected]> added the comment:
Here's the revised code sample:
import pathlib
import urllib.request
path = "Z:\\test.py"
print(f"Stock open: {pathlib.Path(path).as_uri()}")
with urllib.request.urlopen(pathlib.Path(path).as_uri()) as fp:
data = fp.read()
print(f"Pathlib resolved open: {pathlib.Path(path).resolve().as_uri()}")
with urllib.request.urlopen(pathlib.Path(path).resolve().as_uri()) as fp:
data = fp.read()
and here's the output:
Z:\> python test.py
Stock open: file:///Z:/test.py
Pathlib resolved open: file://host/share/test.py
Traceback (most recent call last):
File "C:\Program Files\Python310\lib\urllib\request.py", line 1505, in
open_local_file
stats = os.stat(localfile)
FileNotFoundError: [WinError 2] The system cannot find the file specified:
'\\share\\test.py'
During handling of the above exception, another exception occurred:
Traceback (most recent call last):
File "Z:\test.py", line 14, in <module>
with urllib.request.urlopen(pathlib.Path(path).resolve().as_uri()) as
fp:
File "C:\Program Files\Python310\lib\urllib\request.py", line 216, in
urlopen
return opener.open(url, data, timeout)
File "C:\Program Files\Python310\lib\urllib\request.py", line 519, in open
response = self._open(req, data)
File "C:\Program Files\Python310\lib\urllib\request.py", line 536, in _open
result = self._call_chain(self.handle_open, protocol, protocol +
File "C:\Program Files\Python310\lib\urllib\request.py", line 496, in
_call_chain
result = func(*args)
File "C:\Program Files\Python310\lib\urllib\request.py", line 1483, in
file_open
return self.open_local_file(req)
File "C:\Program Files\Python310\lib\urllib\request.py", line 1522, in
open_local_file
raise URLError(exp)
urllib.error.URLError: <urlopen error [WinError 2] The system cannot find
the file specified: '\\share\\test.py'>
----------
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<https://bugs.python.org/issue46654>
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