George Sakkis <[email protected]> added the comment: > That should have been: last = result[-1]; [last]*s.count(last).
Nice, though that's not equivalent if the objects' identity is significant for what happens next (which typically is the case when ties are preserved). The sorted/bisect solution doesn't have this problem. ---------- _______________________________________ Python tracker <[email protected]> <http://bugs.python.org/issue5669> _______________________________________ _______________________________________________ Python-bugs-list mailing list Unsubscribe: http://mail.python.org/mailman/options/python-bugs-list/archive%40mail-archive.com
