New submission from Christoph Burgmer <cburg...@ira.uka.de>:
locale.format_string doesn't return same result as a normal
"string" % format
directive, but raises a TypeError. See attached test case for Python
2.6.
>>> locale.format_string('%f%%', 1.0)
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
File "/usr/lib/python2.5/locale.py", line 195, in format_string
return new_f % val
TypeError: not enough arguments for format string
>>> '%f%%' % 1.0
'1.000000%'
----------
components: Library (Lib)
files: locale_percents_test.diff
keywords: patch
messages: 91352
nosy: christoph
severity: normal
status: open
title: locale.format_string fails on escaped percentage
versions: Python 2.5, Python 2.6
Added file: http://bugs.python.org/file14665/locale_percents_test.diff
_______________________________________
Python tracker <rep...@bugs.python.org>
<http://bugs.python.org/issue6656>
_______________________________________
_______________________________________________
Python-bugs-list mailing list
Unsubscribe:
http://mail.python.org/mailman/options/python-bugs-list/archive%40mail-archive.com
