New submission from Alex <[email protected]>:
Just like we turn BUILD_LIST; COMPARE_OP (in) into a LOAD_CONST if all
the members are consts, we can do the same for BUILD_SET, instead
turning it into a LOAD_CONST of a frozenset. The following is the
bytecode that is current produced for each datastructure.
>>> dis.dis(lambda o: o in (1,2,3))
1 0 LOAD_FAST 0 (o)
3 LOAD_CONST 3 ((1, 2, 3))
6 COMPARE_OP 6 (in)
9 RETURN_VALUE
>>> dis.dis(lambda o: o in [1,2,3])
1 0 LOAD_FAST 0 (o)
3 LOAD_CONST 3 ((1, 2, 3))
6 COMPARE_OP 6 (in)
9 RETURN_VALUE
>>> dis.dis(lambda o: o in {1,2,3})
1 0 LOAD_FAST 0 (o)
3 LOAD_CONST 0 (1)
6 LOAD_CONST 1 (2)
9 LOAD_CONST 2 (3)
12 BUILD_SET 3
15 COMPARE_OP 6 (in)
18 RETURN_VALUE
----------
components: Interpreter Core
messages: 91506
nosy: alex
severity: normal
status: open
title: BUILD_SET followed by COMPARE_OP (in) can be optimized if all items are
consts
versions: Python 3.2
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Python tracker <[email protected]>
<http://bugs.python.org/issue6690>
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