Eric Smith <e...@trueblade.com> added the comment: This isn't the right forum to ask for help. You should try comp.lang.python, where someone would be happy to explain this to you.
Having said that, here's the explanation: This is not a bug. Disregarding side effects, the expression: a = b or c is essentially the same as: if b: a = b else: a = c So your code is: if (lambda x : x == 'foo'): cond = (lambda x : x == 'foo') else: cond = (lambda x : x == 'bar') And since "(lambda x : x == 'foo')" evaluates to True (it's a lambda, so it's not None), you're really saying: cond = (lambda x : x == 'foo') And your examples follow from that. You can further verify this with your c1 and c2: >>> cond = c1 or c2 >>> cond <function <lambda> at 0x00B3EA30> >>> cond is c1 True So, you're just setting cond to the first of the 2 lambdas. ---------- nosy: +eric.smith resolution: -> invalid stage: -> committed/rejected status: open -> closed type: -> behavior _______________________________________ Python tracker <rep...@bugs.python.org> <http://bugs.python.org/issue6740> _______________________________________ _______________________________________________ Python-bugs-list mailing list Unsubscribe: http://mail.python.org/mailman/options/python-bugs-list/archive%40mail-archive.com
