New submission from lplatypus <[email protected]>:
The documentation for the hash() function says:
"Numeric values that compare equal have the same hash value (even if they are
of different types, as is the case for 1 and 1.0)"
This can be violated when comparing a unicode object with its str equivalent.
Here is an example:
C:\>c:\Python27\python -S
Python 2.7a3 (r27a3:78021, Feb 7 2010, 00:00:09) [MSC v.1500 32 bit (Intel)]
on win32
>>> import sys; sys.setdefaultencoding('utf-8')
>>> unicodeobj = u'No\xebl'
>>> strobj = str(unicodeobj)
>>> unicodeobj == strobj
True
>>> hash(unicodeobj) == hash(strobj)
False
The last response should be True not False.
I tested this on Python 2.7a3/windows, 2.6.4/linux, 2.5.2/linux. The problem
is not relevant to Python 3.0+.
Looking at unicodeobject.c:unicode_hash() and stringobject.c:string_hash(), I
think that this problem would arise for "equal" objects strobj and unicodeobj
when the unicode code points are not aligned with the encoded bytes, ie when:
map(ord, unicodeobj) != map(ord, strobj)
This means that the problem never arises when sys.getdefaultencoding() is
'ascii' or 'iso8859-1'/'latin1'.
----------
components: Interpreter Core
messages: 99084
nosy: ldeller
severity: normal
status: open
title: equal unicode/str objects can have unequal hash
type: behavior
versions: Python 2.5, Python 2.6, Python 2.7
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Python tracker <[email protected]>
<http://bugs.python.org/issue7890>
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