Sebastien Binet <[email protected]> added the comment:
hi Mark,
that may very well be so, but I'd naively standardize on C/Fortran behaviour
(but that's probably my physicist bias)
on my platform, the following piece of C-code:
$ cat test_cmath.c
#include <complex.h>
#include <stdio.h>
int main(int argc, char** argv)
{
complex c = casinh(-2*I);
printf("asinh(-2j) = %g + %gi\n", creal(c), cimag(c));
return 0;
}
/* EOF */
gives:
$ ./a.out
asinh(-2j) = -1.31696 + -1.5708i
cheers,
sebastien.
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