New submission from AdamN <a...@varud.com>:
urlsplit and urlparse place the host into the path when using a default scheme:
(Pdb) urlsplit('regionalhelpwanted.com/browseads/?sn=2',scheme='http')
SplitResult(scheme='http', netloc='', path='regionalhelpwanted.com/browseads/',
query='sn=2', fragment='')
When using default_scheme as referenced in the documentation, it simply doesn't
work:
(Pdb) urlsplit('regionalhelpwanted.com/browseads/?sn=2',default_scheme='http')
*** TypeError: urlsplit() got an unexpected keyword argument 'default_scheme'
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components: Library (Lib)
messages: 106438
nosy: adamnelson
priority: normal
severity: normal
status: open
title: urlsplit and urlparse add extra slash when using scheme
versions: Python 2.6
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Python tracker <rep...@bugs.python.org>
<http://bugs.python.org/issue8818>
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